x^2+3x-4/2x^2-5x+3

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Solution for x^2+3x-4/2x^2-5x+3 equation: 


x in (-oo:+oo)

x^2-((4/2)*x^2)+3*x-(5*x)+3 = 0

x^2-2*x^2+3*x-5*x+3 = 0

3-x^2-2*x = 0

DELTA = (-2)^2-(-1*3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(-1*2) or x = (2-16^(1/2))/(-1*2)

x = -3 or x = 1

x in { -3, 1 }

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